Worked example 1
Find a distance
Find the distance between A(-2, 1) and B(4, 9).
- The coordinate changes are 4 − (-2) = 6 and 9 − 1 = 8.
- Use distance = √(6² + 8²) = √100.
Answer: AB = 10 units
Higher Mathematics
Practise distance and midpoint for Scottish Higher Mathematics with worked examples, clear methods and original interactive questions. Calculate distances and midpoints accurately and use them inside multi-step geometry problems.
The distance formula applies Pythagoras to the horizontal and vertical changes between two coordinate points. Squaring removes the signs, but each coordinate difference must still be formed correctly.
The midpoint formula averages corresponding coordinates. It can also be reversed: if one endpoint and the midpoint are known, double each midpoint coordinate and subtract the known endpoint coordinate.
Worked example 1
Find the distance between A(-2, 1) and B(4, 9).
Answer: AB = 10 units
Worked example 2
Find the midpoint of C(-5, 4) and D(7, −2).
So: Midpoint = (1, 1)
Worked example 3
A(-2, 5) and B have midpoint M(3, −1). Find B.
Answer: B = (8, −7)
Worked example 4
P(0, 0), Q(6, 2) and R(2, 6). Show that PQ and PR have equal length
So: PQ = PR = √40 = 2√10, so triangle PQR is isosceles
Exam reminder
Write the coordinate changes or averages before substituting. If a question asks you to prove lengths are equal, comparing their squared distances is sufficient and avoids unnecessary rounding.
Continue with the methods that connect most closely to this topic.