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SQA National 5 Mathematics

The quadratic formula

Solving quadratics when factorising is not efficient.

Before you start

  • Identify a, b and c from ax² + bx + c = 0
  • Substitute negative values carefully using brackets.
National 5 Mathematics lesson

Explanation

The quadratic formula solves any quadratic equation written as ax² + bx + c = 0.

It is most useful when a quadratic does not factorise neatly. Substitute a, b and c, then simplify carefully.

At National 5, method marks often come from correct substitution before calculator evaluation.

Visual support

Substitute into the quadratic formula

ax² + bx + c = 0

x = (-b ± √(b² − 4ac)) / 2a

For x² + 5x + 3 = 0: a = 1, b = 5, c = 3

Key formulae and rules

  • x = (-b ± √(b² − 4ac)) / 2a

Watch out

Forgetting to put a negative b in brackets.

Check

Substitute each solution back into the equation. A quick check catches most sign errors.

Exam tip

Write the formula first, then a clean substitution line. This protects method marks even if arithmetic slips.

Calculator tip

Enter the numerator in brackets, especially when using a negative b or the ± answers separately.

Worked examples

Worked example 1

Use the formula

Solve x² + 5x + 3 = 0.

  1. Here a = 1, b = 5, c = 3
  2. Substitute: x = (-5 ± √(25 − 12)) / 2
  3. Simplify: x = (-5 ± √13) / 2.

Answer: x = (-5 + √13) / 2 or x = (-5 − √13) / 2

Worked example 2

Round calculator answers

Solve 2x² − 3x − 4 = 0, correct to 2 decimal places.

  1. a = 2, b = −3, c = −4.
  2. x = (3 ± √(9 + 32)) / 4
  3. x = (3 ± √41) / 4

So: x = 2.35 or x = −0.85

Worked example 3

Keep negative b under control

Solve x² − 6x + 2 = 0.

  1. a = 1, b = −6, c = 2.
  2. x = (6 ± √(36 − 8)) / 2
  3. x = (6 ± √28) / 2 = 3 ± √7

Answer: x = 3 + √7 or x = 3 − √7

Watch out

  • Forgetting to put a negative b in brackets.
  • Using 2a as 2 + a.
  • Rounding too early before the final answer.