Question
Differentiate y = (2x2 + 3)4
Higher Maths worked question
Practise using the chain rule to differentiate a composite power, then check each stage with a full worked solution.
Differentiate y = (2x2 + 3)4
Let u = 2x2 + 3, so y = u4
This separates the quadratic inner function from the outer fourth power.
dy/du = 4u3 and du/dx = 4x
Differentiate the outer power and the inner quadratic separately.
dy/dx = (dy/du)(du/dx) = 4u3 × 4x
The chain rule multiplies the outer derivative by the inner derivative.
dy/dx = 16x(2x2 + 3)3
Multiply the coefficients and replace u with 2x2 + 3
Final answer: dy/dx = 16x(2x2 + 3)3
Treat the bracket as one inner function. Differentiating the outer fourth power produces 4(2x2 + 3)3, and the chain rule then requires multiplication by the inner derivative 4x.
The outer power must reduce from 4 to 3, and the final derivative must contain the factor 4x from differentiating 2x2 + 3.