Homework
Higher Mathematics homework set
Scottish Higher Mathematics | 25-40 minutes | Mixed practice
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Pupil instructions
Answer each question in your jotter or on the printed sheet. Show enough working for your teacher to see your method.
For y = 3x² + 12x, state where the function is increasing.
Support hint: Increasing means dy/dx > 0
For y = 4x³ − x, find the gradient at x = 0.
Support hint: Differentiate before substituting.
A geometric sequence has u₁ = 8 and ratio 0.5. State uₙ.
Support hint: The exponent is n − 1 because u₁ is the first term.
In triangle ABC, a = 13, A = 60° and B = 30°. Use the sine rule to express b exactly
Support hint: Match each side with its opposite angle.
Solve sin θ = −√32 for 0° ≤ θ < 360° .
Support hint: Use CAST or the graph to locate the signs.
Find the discriminant of 2x² + 5x + 2 = 0 and state the nature of the roots.
Support hint: Identify a, b and c before substituting.
State the multiplier for growth of 8% per time period.
Support hint: Growth multipliers are above 1; decay multipliers are below 1.
Find the area under y = 4x + 2 from x = 0 to x = 2.
Support hint: The line is above the axis, so the integral gives the area.
Find a unit vector in the direction of (5, 12).
Support hint: A unit vector has length 1.
f(x) = 5x + 6 and g(x) = x² + 5. Find f(g(x))
Support hint: Put the whole expression for g(x) inside f.
Use the factor theorem to test whether x + 1 is a factor of f(x) = x² + 2x + 1.
Support hint: For x − a, substitute x = a.
State the centre and radius of (x − 4)² + (y − 4)² = 25.
Support hint: The bracket signs are opposite to the centre coordinates.
Answer key
x > −2
differentiation: dy/dx = 6x + 12. This is positive when x > −2
-1
differentiation: dy/dx = 12x² − 1. At x = 0, the gradient is −1
uₙ = 8(0.5)ⁿ⁻¹
recurrence sequences: Use uₙ = arⁿ⁻¹
13/√3
trigonometry: Use b/sin B = a/sin A, then substitute the exact sine values
240°, 300°
trigonometry: The related acute angle is 60°. Use the quadrants where sin is negative.
9; two real roots
polynomials quadratics: Use b² − 4ac = 5² − 4(2)(2) = 9
1.08
exponentials logarithms: Add 8% from 100%, then write as a decimal multiplier.
12
integration: Integrate to 2x² + 2x, then evaluate from 0 to 2
(513, 1213)
vectors: Divide each component by the magnitude 13.
5x² + 31
algebra functions: Apply g first: f(g(x)) = 5(x² + 5) + 6 = 5x² + 31
Yes, because f(a) = 0
polynomials quadratics: Substitute x = −1. The value is 0, so x + 1 is a factor
Centre (4, 4), radius 5
straight line circles: Compare with (x − h)² + (y − k)² = r²; watch the signs inside brackets.